Simplifying Radicals

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Simplifying Radicals: meaning, method and solved example (Algebra 1) – Maths PDF


In short: Simplifying radicals means rewriting a square root so that no perfect square factor remains under the radical sign, for example √72 becomes 6√2.

Algebra 1Numbers and OperationsN-RN.A.2

What is Simplifying Radicals?

Although \(\sqrt{72}\) is exact, it looks untidy, and simplifying radicals pulls out every perfect square hiding inside it, leaving a whole number in front and a smaller number under the sign.

The tool is the product rule, \(\sqrt{ab} = \sqrt{a}\cdot\sqrt{b}\) for \(a, b \ge 0\). Since \(72 = 36 \cdot 2\) and \(\sqrt{36} = 6\), you get \(\sqrt{72} = 6\sqrt{2}\). A radical is simplified when its radicand has no square factor greater than 1.

How to spot it

  • Simplifying radicals is needed when an answer is left with a big radicand such as 72 or 180.
  • The instructions say simplify, write in simplest radical form or give an exact answer.
  • A Pythagorean theorem result is not a perfect square, so the side length stays a radical.
  • Knowing your squares up to 144 helps you test the radicand quickly.

The method

  1. Run through the perfect squares you know and find the largest one that divides the radicand evenly.
  2. Split the radicand into that square times the leftover factor.
  3. Take the square root of the perfect square and write it outside the radical.
  4. Check that the number left inside has no perfect square factor; if it does, repeat.
723626perfect squarestays inside√36 = 6 comes out√72 = 6√2
72 = 36 × 2, so √72 = √36 · √2 = 6√2.

Simplifying Radicals: solved example

Problem

A square garden plot has an area of 180 square feet. State the side exactly, with a radical, and then approximate it with two decimal places.

Solution

The side is \(\sqrt{180}\). The largest perfect square dividing 180 is 36, since \(180 = 36 \cdot 5\).

So \(\sqrt{180} = \sqrt{36}\cdot\sqrt{5} = 6\sqrt{5} \approx 6(2.2361) \approx 13.42\). The side is \(6\sqrt{5}\) feet, about 13.42 feet.

Try it

Question 1

Simplify \(\sqrt{48}\).

Show the answer

\(48 = 16 \cdot 3\), so \(\sqrt{48} = 4\sqrt{3}\).

Question 2

Simplify \(3\sqrt{50}\).

Show the answer

\(\sqrt{50} = \sqrt{25}\cdot\sqrt{2} = 5\sqrt{2}\), so \(3\sqrt{50} = 15\sqrt{2}\).

Simplifying Radicals vs. Square Root

A plain square root asks for the number that multiplies by itself to give the radicand. Simplification does not change the value; it only rewrites an irrational root in a cleaner form, such as 6√2 for √72, so answers can be compared and added with like radicals.

Square Root

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