Binomial Distribution

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Binomial Distribution: meaning, method and solved example (AP Statistics) – Maths PDF


In short: Binomial distribution gives the probability of exactly k successes in n independent trials that each have the same success probability p and only two possible outcomes.

AP StatisticsProbabilityAP Statistics Unit 2

What is Binomial Distribution?

A binomial distribution counts successes in a fixed number of repeated tries. Think of guessing on 8 multiple-choice questions and counting how many you get right.

Four conditions must hold: a fixed number of trials \(n\); each trial is a success or failure; trials are independent; and the success probability \(p\) is the same every time. Then

\[P(X = k) = \binom{n}{k}\,p^k\,(1-p)^{n-k}\]

with mean \(\mu = np\) and standard deviation \(\sigma = \sqrt{np(1-p)}\).

How to spot it

  • A problem repeats the same simple trial a fixed number of times and counts the successes.
  • Each attempt is yes or no: a basket made or missed, a part defective or fine, a guess right or wrong.
  • The question asks for the chance of exactly, at least or at most a certain number of successes.
  • Sampling is done without replacement from a very large population, so independence is approximately true.

The method

  1. Check the four conditions and define a success clearly; identify \(n\) and \(p\).
  2. For an exact count, compute \(\binom{n}{k}p^k(1-p)^{n-k}\).
  3. For “at least” statements, use the complement when it is shorter, such as \(1 – P(X = 0)\).
  4. Find the mean \(np\) and standard deviation \(\sqrt{np(1-p)}\) to describe the typical count.
0.1000.2670.3110.2080.0870.0230.0040123456number of correct guesses, n = 8, p = 0.25
Exactly 3 correct answers (raspberry bar) has probability about 0.208.

Binomial Distribution: solved example

Problem

A quiz has 8 multiple-choice questions with 4 options each. A student guesses every answer. Find the probability of exactly 3 correct answers, and the mean and standard deviation of the number correct.

Solution

Here \(n = 8\), \(p = 0.25\), \(k = 3\).

\(P(X = 3) = \binom{8}{3}(0.25)^3(0.75)^5 = 56 \times 0.015625 \times 0.2373 \approx\) 0.2076.

Mean: \(8(0.25) = 2\) correct. Standard deviation: \(\sqrt{8(0.25)(0.75)} = \sqrt{1.5} \approx 1.22\).

Try it

Question 1

Using the same quiz, find the probability of at least one correct answer.

Show the answer

\(1 – P(X = 0) = 1 – (0.75)^8 \approx 1 – 0.1001 = 0.8999\).

Question 2

A bakery’s loaves are underweight 5% of the time. In a batch of 20, find the expected number of underweight loaves.

Show the answer

\(np = 20(0.05) = 1\) loaf.

Binomial Distribution vs. Normal Distribution

The binomial distribution counts whole-number successes, so its bars are separate. The normal distribution is a smooth, continuous curve. When \(np\) and \(n(1-p)\) are both at least 10, the bars of the binomial distribution look close to a bell and the normal curve gives a good approximation.

Normal Distribution

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