Polar Form of a Complex Number

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Polar Form of a Complex Number: meaning, method and solved example (Precalculus) – Maths PDF


In short: The polar form of a complex number swaps its two rectangular parts a + bi for a range r and a bearing θ, giving r(cos θ + i sin θ) as an equivalent name for the same point.

PrecalculusNumbers and OperationsN-CN.B.4

What is Polar Form of a Complex Number?

The polar form of a complex number describes a point by how far away it is and which way it lies, like giving a ship’s range and bearing rather than its east-west and north-south offsets.

For \(z = a + bi\), the modulus is \(r = \sqrt{a^2 + b^2}\) and the argument \(\theta\) satisfies \(\cos\theta = \frac{a}{r}\) and \(\sin\theta = \frac{b}{r}\). Then \(z = r(\cos\theta + i\sin\theta)\), often abbreviated \(r\,\text{cis}\,\theta\). The angle is usually chosen between \(0\) and \(2\pi\), and adding \(2\pi\) gives the same number.

How to spot it

  • Products, quotients or powers are needed, and the polar form of a complex number makes them far easier.
  • The task asks for the modulus and argument, or the distance and angle from the origin.
  • A number is given as r(cos θ + i sin θ) and you must return to a + bi.
  • The complex plane is drawn with a point and a ray from the origin.

The method

  1. Identify the real part \(a\) and the imaginary coefficient \(b\).
  2. Compute the modulus \(r = \sqrt{a^2 + b^2}\).
  3. Find the quadrant from the signs of \(a\) and \(b\), then use the reference angle \(\tan^{-1}\left|\frac{b}{a}\right|\) to get \(\theta\).
  4. Write the polar form of the complex number, \(r(\cos\theta + i\sin\theta)\), and test it by expanding.
3√3 – 3ir = 6-30°-33√3real axis →, imaginary axis ↑z = 6(cos 330° + i sin 330°)
The point 3√3 – 3i lies 6 units from the origin at an angle of 330°.

Polar Form of a Complex Number: solved example

Problem

Write \(z = 3\sqrt{3} – 3i\) in polar form.

Solution

The modulus is \(r = \sqrt{(3\sqrt{3})^2 + (-3)^2} = \sqrt{27 + 9} = 6\). The point has a positive real part and a negative imaginary part, so it is in Quadrant IV.

The reference angle is \(\tan^{-1}\frac{3}{3\sqrt{3}} = 30^{\circ}\), so \(\theta = 330^{\circ}\). Therefore \(z = 6(\cos 330^{\circ} + i\sin 330^{\circ})\).

Try it

Question 1

Convert \(4(\cos 90^{\circ} + i\sin 90^{\circ})\) to the form \(a + bi\).

Show the answer

\(4(0 + i\cdot 1) = 4i\).

Question 2

State the modulus and argument for \(z = -5\).

Show the answer

The modulus is 5, and the point lies on the negative real axis, so the argument is \(\pi\).

Polar Form of a Complex Number vs. Polar Coordinates

Polar coordinates \((r, \theta)\) name a point in an ordinary plane. The form discussed here applies the same idea to a number in the complex plane, where multiplication also becomes meaningful: moduli multiply and arguments add. The picture is shared, but the second one carries arithmetic.

Polar Coordinates

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