Unit Circle

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Unit Circle: meaning, method and solved example (Algebra 2) – Maths PDF


In short: The unit circle has radius 1 and sits on the origin; rotating to an angle θ lands on the point (cos θ, sin θ), so sines and cosines become plain coordinates.

Algebra 2TrigonometryF-TF.A.2

What is Unit Circle?

The unit circle is a ruler for angles. Begin at (1, 0), walk counterclockwise around the rim by an angle \(\theta\), and read your landing spot: its horizontal coordinate is \(\cos\theta\), its vertical coordinate is \(\sin\theta\).

The curve obeys \(x^2 + y^2 = 1\). Turning counterclockwise from the positive x-axis counts as a positive angle, whether you label it in degrees or radians. With a radius of exactly 1, the ratio \(\tan\theta = \frac{\sin\theta}{\cos\theta}\) is just the slope of the radius.

How to spot it

  • A question asks for exact values of sine or cosine at angles like 30°, 45°, 60° or their multiples.
  • An angle is given in radians, such as 4π/3, and a point on a circle is wanted.
  • A problem lists coordinates like (-1/2, -√3/2) and asks which angle they belong to.
  • You need the sign of a trig value and must decide which quadrant the angle ends in.

The method

  1. Convert the angle to degrees if helpful and locate its terminal side by quadrant.
  2. Find the reference angle between the terminal side and the x-axis.
  3. Use the special-angle values \(\left(\frac{\sqrt{3}}{2}, \frac{1}{2}\right)\), \(\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)\), \(\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right)\) for the first quadrant.
  4. Attach signs from the quadrant: cosine is the x-sign, sine is the y-sign.
(1, 0)(-1, 0)(0, 1)(0, -1)(-1/2, -sqrt3/2)240° = 4π/3cos = -1/2sin = -sqrt3/2
At 240° (4π/3) the point on the circle is (-1/2, -√3/2).

Unit Circle: solved example

Problem

Find the coordinates of the point on the unit circle at \(\theta = \frac{4\pi}{3}\) radians, and verify that it lies on the circle.

Solution

Because \(\frac{4\pi}{3}\) radians equals \(240^{\circ}\), the ray lands 60° beyond the negative x-axis. With a 60° gap, the magnitudes are \(\frac{1}{2}\) for cosine and \(\frac{\sqrt{3}}{2}\) for sine, and Quadrant III makes both negative.

The point is \(\left(-\frac{1}{2}, -\frac{\sqrt{3}}{2}\right)\). Check: \(\frac{1}{4} + \frac{3}{4} = 1\).

Try it

Question 1

Find \(\tan\frac{3\pi}{4}\) using the circle.

Show the answer

The point is \(\left(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)\), so \(\tan = \frac{\sqrt{2}/2}{-\sqrt{2}/2} = -1\).

Question 2

A point \(\left(\frac{3}{5}, y\right)\) lies on the circle in Quadrant IV. Find \(y\).

Show the answer

\(y^2 = 1 – \frac{9}{25} = \frac{16}{25}\), and in Quadrant IV \(y\) is negative: \(y = -\frac{4}{5}\).

Unit Circle vs. Radian

The circle is a drawing: every point exactly 1 away from the origin. A radian is a size of turn, namely the turn that sweeps out a curved distance of 1 along it. Radians label locations here, yet a measuring unit and a shape are different things.

Radian

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