Factorial

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Factorial: meaning, method and solved example (Precalculus) – Maths PDF


In short: A factorial, written n!, multiplies a whole number by every smaller positive whole number, and the result counts the different line-ups possible for n distinct things.

PrecalculusProbabilityS-CP.B.9

What is Factorial?

A factorial is shorthand for a long countdown multiplication. Seven distinct pastries in a display row can be ordered \(7!\) ways: 7 candidates for spot one, 6 left for spot two, and so forth.

By definition \(n! = n(n-1)(n-2)\cdots 2\cdot 1\) for a positive integer \(n\), and \(0! = 1\) by agreement, so that formulas for counting still work. Values grow extremely fast: \(5! = 120\) but \(10! = 3{,}628{,}800\). Factorials also satisfy \(n! = n\cdot(n-1)!\).

How to spot it

  • An exclamation mark follows a whole number or a variable, as in 6! or (n + 2)!.
  • A problem asks in how many orders items can be arranged, lined up or scheduled.
  • A counting formula for permutations or combinations contains n! over a product of other factorials.
  • A fraction of factorials, such as 10!/(7!3!), must be simplified without a calculator.

The method

  1. Write out the product from \(n\) down to 1, or from \(n\) down to the point where cancellation starts.
  2. In a fraction, cancel the shared tail: \(\frac{10!}{7!} = 10\cdot 9\cdot 8\).
  3. Remember \(0! = 1\) and \(1! = 1\).
  4. Multiply what remains and keep an eye on very large totals, which may need a calculator.
54321××××1st seat2nd3rd4th5th5! = 5 × 4 × 3 × 2 × 1 = 120 arrangements
Five items fill five spots in 5 × 4 × 3 × 2 × 1 = 120 ways.

Factorial: solved example

Problem

A café displays 7 different pastries in a row. Find the number of possible orders, and then compute \(\frac{10!}{7!\,3!}\).

Solution

The orders number \(7! = 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1 = 5{,}040\).

For the fraction, cancel \(7!\): \(\frac{10\cdot 9\cdot 8}{3\cdot 2\cdot 1} = \frac{720}{6} = 120\). The results are 5,040 and 120.

Try it

Question 1

What is \(0!\), and why is the answer useful?

Show the answer

\(0! = 1\). It lets counting formulas such as \(\frac{n!}{n!\,0!}\) equal 1 for choosing all or none of the items.

Question 2

Simplify \(\frac{(n+1)!}{(n-1)!}\).

Show the answer

\(\frac{(n+1)\,n\,(n-1)!}{(n-1)!} = (n+1)n\).

Factorial vs. Permutation

The factorial takes one number and counts line-ups of all n items. A permutation counts line-ups of only a chosen few, like 3 medal winners from 12 runners, which equals \(\frac{12!}{9!}\). Permutations are assembled from factorials, yet the two ideas differ.

Permutation

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