Algebra 2 Radians and the Unit Circle Test Solutions and Scoring (PDF)

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This unit circle test answers for Algebra 2 covers radians and the unit circle (Common Core F-TF.A.1, F-TF.A.2, F-TF.A.3), with a free PDF to print.

Use this answer key and scoring guide to grade the test on radians and the unit circle (F-TF.A.1). Each solution shows the full reasoning, and the scoring note explains how many points to award for correct setup, correct work, and a correct final answer. Partial credit rewards a sound method even when a small arithmetic slip changes the result.

Algebra 2 · Common Core State Standards: F-TF.A.1, F-TF.A.2, F-TF.A.3

Unit circle test answers: worked solutions

Question 1 – Convert angles [2 pts]

  1. \(150 \cdot \frac{\pi}{180} = \frac{5\pi}{6}\)

  2. \(\frac{5\pi}{3} \cdot \frac{180}{\pi} = 300\)

(a) \(\frac{5\pi}{6}\); (b) \(300^{\circ}\)

Scoring: 1 point for each conversion.

Question 2 – Arc length [2 pts]

\(s = 8 \cdot \frac{5\pi}{6} = \frac{20\pi}{3}\).

20π/3 cm

Scoring: 1 point for s = rθ, 1 point for the value.

Question 3 – Exact values [3 pts]

0° (0)(1, 0)30° (π/6)(√3/2, 1/2)45° (π/4)(√2/2, √2/2)60° (π/3)(1/2, √3/2)90° (π/2)(0, 1)
Quadrant I: the points (cos θ, sin θ) for the special angles.
  1. \(\frac{\sqrt{3}}{2}\)

  2. \(\frac{\sqrt{2}}{2}\)

  3. \(\frac{\sqrt{3}}{3}\)

(a) \(\frac{\sqrt{3}}{2}\); (b) \(\frac{\sqrt{2}}{2}\); (c) \(\frac{\sqrt{3}}{3}\)

Scoring: 1 point for each value.

Question 4 – Reference angles [3 pts]

  1. Quadrant III, reference \(\frac{\pi}{3}\): cosine negative, \(- \frac{1}{2}\).

  2. Quadrant IV, reference \(\frac{\pi}{6}\): sine negative, \(- \frac{1}{2}\).

  3. Quadrant III, reference \(\frac{\pi}{4}\): tangent positive, \(1\).

(a) \(- \frac{1}{2}\); (b) \(- \frac{1}{2}\); (c) \(1\)

Scoring: 1 point for each value.

Question 5 – Solve for the angle [2 pts]

Reference angle \(\frac{\pi}{4}\); cosine is positive in quadrants I and IV.

\(\theta = \frac{\pi}{4}\) or \(2\pi – \frac{\pi}{4} = \frac{7\pi}{4}\).

\(\theta = \frac{\pi}{4}, \frac{7\pi}{4}\)

Scoring: 1 point for each solution.

Question 6 – Coterminal and negative angles [2 pts]

\(\frac{9\pi}{4} – 2\pi = \frac{\pi}{4}\), so \(\sin\frac{9\pi}{4} = \frac{\sqrt{2}}{2}\).

\(-\frac{2\pi}{3}\) is in quadrant III with reference angle \(\frac{\pi}{3}\): \(-\frac{1}{2}\).

\(\frac{\sqrt{2}}{2}\) and \(-\frac{1}{2}\)

Scoring: 1 point for each value.

Question 7 – Point on the unit circle [2 pts]

Reference angle \(\frac{\pi}{4}\), quadrant II: x negative, y positive.

135° (3π/4)(-√2/2, √2/2)
P = (-√2/2, √2/2).

\(P = \left(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)\)

Scoring: 1 point for each coordinate.

Question 8 – Bike wheel [2 pts]

\(s = 14 \cdot \frac{5\pi}{2} = 35\pi\) inches, about 110 inches.

35π in, about 110 in

Scoring: 1 point for s = rθ, 1 point for the value.

Question 9 – Find the error [2 pts]

\(\tan\frac{\pi}{2} = \frac{\sin(\pi/2)}{\cos(\pi/2)} = \frac{1}{0}\), which is undefined. A zero in the denominator makes tangent undefined, not zero.

tan(π/2) is undefined

Scoring: 1 point for the ratio, 1 point for the conclusion.

Total score

Total

20 points

Key facts behind this unit circle test answers

Key facts
  • θ = s / r, and 180° = π radians.
  • Arc length s = rθ when θ is in radians.
  • Point on the unit circle at θ: (cos θ, sin θ).
  • tan θ = sin θ / cos θ; cos² θ + sin² θ = 1.
  • Use reference angles and quadrant signs for exact values.

How to use this unit circle test answers

Score your test with the point values shown for each question. Then read the worked solution of every question where you lost points and note the method to review.

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Algebra 2 Radians and the Unit Circle Test Solutions and Scoring

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