6th Grade Area of Triangles and Polygons Quiz: 10 Questions with Explanations

A \(40\text{ cm}^{2}\)B \(20\text{ cm}^{2}\)C \(13\text{ cm}^{2}\)D \(26\text{ cm}^{2}\)

Half of \(8 \times 5\) is 20. Forgetting the half gives 40.

A \(14\text{ m}^{2}\)B \(28\text{ m}^{2}\)C \(11\text{ m}^{2}\)D \(35\text{ m}^{2}\)

Area = base x height = \(7 \times 4 = 28\). The slanted side length is not used.

A 4B 12C 144D 8

24 = (1/2) x b x \(6 = 3\)b, so b = 8.

A 64B 40C 32D 24

(\(6 + 10\)) / \(2 \times 4 = 32\).

A 24B 28C 20D 16

\(6 \times 4 – 2 \times 2 = 24 – 4 = 20\).

A The triangle has twice the areaB The triangle has half the areaC They have the same areaD The triangle has one third of the area

The parallelogram has area 60 and the triangle has area (1/2)(10)(6) = 30.

A They have the same areaB The first triangleC The second triangleD Cannot be determined

(1/2)(9)(4) = 18 and (1/2)(6)(6) = 18.

A 20B 40C 15D 24

Base 8 and height 5: (1/2)(8)(5) = 20.

A \(60\text{ m}^{2}\)B \(90\text{ m}^{2}\)C \(15\text{ m}^{2}\)D \(75\text{ m}^{2}\)

60 + (1/2)(10)(3) = \(60 + 15 = 75\).

A 30B 6C 216D 15

\(18 + 12 = 30\). The areas add.