Arithmetic Series

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Arithmetic Series: meaning, method and solved example (Algebra 2) – Maths PDF


In short: An arithmetic series is what you get by adding up an arithmetic sequence, whose terms climb or drop by a fixed step; the total is the number of terms times the mean of the two end terms.

Algebra 2AlgebraA-SSE.B.4

What is Arithmetic Series?

An arithmetic series is what you get when you add up a list of numbers that step by a fixed amount, like 14, 17, 20, 23. The list itself is a sequence; the sum is the series.

With first term \(a_1\), common difference \(d\) and \(n\) terms, the last term is \(a_n = a_1 + (n – 1)d\). Adding the first \(n\) terms gives \(S_n = \frac{n(a_1 + a_n)}{2}\). It works since every pair taken from opposite ends of the list, first with last, second with next-to-last, has an identical total.

How to spot it

  • A story stacks things in rows or layers where each row has a fixed number more than the one before.
  • The terms of a list increase by the same amount, and the problem asks for the total of that arithmetic series.
  • Notation such as S_20 or a sigma sum of a linear expression in k appears.
  • Adding by hand would take dozens of steps, so a shortcut is clearly needed.

The method

  1. Find the first term \(a_1\), the common difference \(d\) and the number of terms \(n\).
  2. Compute the last term with \(a_n = a_1 + (n – 1)d\) if it is not given.
  3. Substitute into \(S_n = \frac{n(a_1 + a_n)}{2}\).
  4. Finish the arithmetic and name the unit, such as musicians or dollars.
141720232629matching ends: 14 + 29 = 17 + 26 = 20 + 23 = 43S = 3 x 43 = 129
Pairs from opposite ends all total 43, so six terms add to 3 x 43 = 129.

Arithmetic Series: solved example

Problem

A high school marching band lines up in 14 rows for a halftime shape. Row one holds 5 musicians and every later row holds 2 more than the row in front. Count the band.

Solution

Read off \(a_1 = 5\), \(d = 2\) and \(n = 14\). The back row therefore has \(a_{14} = 5 + 13(2) = 31\) players.

Total: \(S_{14} = \frac{14(5 + 31)}{2} = 7 \times 36 = 252\). The band has 252 musicians.

Try it

Question 1

Find the sum \(1 + 3 + 5 + \cdots + 79\), the first 40 odd numbers.

Show the answer

\(S_{40} = \frac{40(1 + 79)}{2} = 1{,}600\).

Question 2

Find \(S_{12}\) when \(a_1 = -5\) and \(d = 4\).

Show the answer

\(a_{12} = -5 + 11(4) = 39\), so \(S_{12} = \frac{12(-5 + 39)}{2} = 204\).

Arithmetic Series vs. Geometric Series

Here a fixed amount is added at every step. Over in the geometric kind, a fixed multiplier is applied instead. The list 5, 10, 15, 20 adds 5 each time, whereas 5, 10, 20, 40 doubles each time, so the two sums need different formulas.

Geometric Series

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