Law of Sines

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Law of Sines: meaning, method and solved example (Geometry) – Maths PDF


In short: The law of sines declares that every side of a triangle divided by the sine of the corner facing it produces one shared number, a key for solving slanted triangles.

GeometryTrigonometryG-SRT.D.10

What is Law of Sines?

The law of sines ties edges to corners in any triangle, square-cornered or not. Name the edges \(a, b, c\) and the corners facing them \(A, B, C\); then \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\).

Reach for it when you hold two corners plus one edge, or two edges plus a corner that faces one of them. That second situation can be ambiguous: the data may fit zero, one or two triangles, so test whether the supplement \(180^{\circ} – B\) also works.

How to spot it

  • A slanted triangle gives one edge together with the corner facing it.
  • Two corners are known, so the third follows from \(180^{\circ}\), and one edge is known.
  • A surveying, sailing or navigation story gives two bearings and one distance.
  • Two fractions are set equal, each with an edge on top and the sine of the facing corner below.

The method

  1. Label each side with the lowercase letter of the angle it faces.
  2. Find any missing angle with the angle sum of \(180^{\circ}\).
  3. Choose two ratios that include the one complete pair, and set them equal.
  4. Cross-multiply and solve; in the SSA case, check whether \(180^{\circ} – B\) gives a second triangle.
ABC40°65°75°c ≈ 18.0b ≈ 16.9a = 12a / sin A = 12 / 0.6428≈ 18.67 for all three
Each side over the sine of its facing angle gives the same number, about 18.67.

Law of Sines: solved example

Problem

In triangle \(ABC\), \(A = 40^{\circ}\), \(B = 65^{\circ}\) and side \(a = 12\). Find \(b\) and \(c\). Use \(\sin 40^{\circ} \approx 0.6428\), \(\sin 65^{\circ} \approx 0.9063\), \(\sin 75^{\circ} \approx 0.9659\).

Solution

The third angle is \(C = 180 – 40 – 65 = 75^{\circ}\). The known pair is \(a\) and \(A\), giving the common ratio \(\frac{12}{0.6428} \approx 18.67\).

Then \(b = 18.67 \times 0.9063 \approx 16.9\) and \(c = 18.67 \times 0.9659 \approx 18.0\). The missing sides are \(b \approx 16.9\) and \(c \approx 18.0\).

Try it

Question 1

In a triangle, \(a = 14\), \(b = 10\) and \(A = 70^{\circ}\). Find angle \(B\). Use \(\sin 70^{\circ} \approx 0.9397\).

Show the answer

\(\sin B = \frac{10 \times 0.9397}{14} \approx 0.6712\), so \(B \approx 42.2^{\circ}\). The other candidate, \(137.8^{\circ}\), would make the angle sum exceed \(180^{\circ}\) with \(70^{\circ}\), so it is rejected.

Question 2

A hiker knows two trail lengths and the turn between them. Is the law of sines a good first step?

Show the answer

No. No edge faces a known corner yet, so start with the law of cosines to get the third edge.

Law of Sines vs. Law of Cosines

This law needs a facing pair: an edge together with the corner across from it. Its cousin handles the cases without such a pair, namely two edges around a corner, or three edges and no corner. Inventory the pieces you hold, then pick the law that fits them.

Law of Cosines

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