Limit at Infinity

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Limit at Infinity: meaning, method and solved example (AP Calculus AB) – Maths PDF


In short: A limit at infinity reports the height a graph levels off at when x runs endlessly to the right or to the left, and so it pinpoints any horizontal asymptote.

AP Calculus ABCalculusAP Calculus AB Unit 1

What is Limit at Infinity?

A limit at infinity tells you the long-run behavior of a function: what height the graph levels off at far out to the right, or far out to the left. Infinity is not a number you can plug in; it is a direction in which \(x\) keeps growing.

We write \(\lim_{x \to \infty} f(x) = L\) when the outputs stay as close to \(L\) as desired once \(x\) is large enough. The line \(y = L\) is then a horizontal asymptote. If the outputs grow without bound instead, the result is written \(\infty\) or \(-\infty\), and no finite value exists.

How to spot it

  • The question asks for a limit at infinity: what happens to f(x) when x becomes extremely large or extremely negative.
  • A rational function has the same highest power in the numerator and denominator.
  • A story asks about long-term behavior, such as the amount of medicine in the blood after many hours.
  • A graph flattens toward a dashed horizontal line on the far right or far left.

The method

  1. Identify the highest power of \(x\) in the denominator.
  2. Divide each term, top and bottom, by that power, as a limit at infinity of a fraction requires.
  3. Replace each fraction of the form \(\frac{c}{x^k}\) by 0, since it vanishes for huge \(x\).
  4. Read off the remaining ratio; if the numerator’s degree is larger, the outputs grow without bound.
horizontal asymptote y = 3x = 10: 2.63x = 20: 2.84x = 60: 2.95x grows to the right
As x increases, f(x) = (6x² – 5x)/(2x² + 9) climbs toward 3.

Limit at Infinity: solved example

Problem

Find \(\lim_{x \to \infty}\dfrac{6x^2 – 5x}{2x^2 + 9}\).

Solution

The highest power in the denominator is \(x^2\). Divide every term by it: \(\dfrac{6 – \frac{5}{x}}{2 + \frac{9}{x^2}}\).

As \(x\) grows, \(\frac{5}{x} \to 0\) and \(\frac{9}{x^2} \to 0\), leaving \(\frac{6}{2}\). The value is 3, so \(y = 3\) is a horizontal asymptote.

Try it

Question 1

Find \(\lim_{x \to -\infty}\frac{8}{x – 3}\).

Show the answer

The denominator grows large in size, so the fraction shrinks to 0.

Question 2

Find \(\lim_{x \to \infty}\frac{x^3 + 1}{5x^2}\).

Show the answer

The numerator’s degree is higher, so the outputs grow without bound: \(\infty\).

Limit at Infinity vs. Asymptote

The line is a picture on the graph, while the limit is a number computed with algebra. Evaluating the long-run height gives the number L, and then \(y = L\) is the asymptote. A graph can approach the line from above or below, and for some functions it even crosses the line before settling.

Asymptote

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