Product Rule

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Product Rule: meaning, method and solved example (AP Calculus AB) – Maths PDF


In short: Product rule finds the derivative of two functions multiplied together: differentiate the first and keep the second, then keep the first and differentiate the second, and add the results.

AP Calculus ABCalculusAP Calculus AB Unit 2

What is Product Rule?

The product rule exists because, when two changing quantities are multiplied, the result changes for two reasons at once: the first one moves, and the second one moves. The rule adds both effects.

For differentiable functions \(u\) and \(v\):

\[\frac{d}{dx}\left[u\,v\right] = u^{\prime}v + u\,v^{\prime}\]

Picture a rectangle with sides \(u\) and \(v\) that are both growing. The extra area comes from a thin strip along each side, and the tiny corner square is negligible.

How to spot it

  • The function is two expressions in x multiplied, such as (2x^3 – x)(x^2 + 5) or x times sin x.
  • Expanding the product first would be long or impossible, for example when a trig function is one factor.
  • A problem gives the values of f, g, f’ and g’ at one input and asks about the derivative of f times g.
  • A rate depends on a product, such as revenue equals price times quantity with both changing.

The method

  1. Name the two factors: \(u\) is the first expression and \(v\) is the second.
  2. Differentiate each one separately to get \(u^{\prime}\) and \(v^{\prime}\).
  3. Assemble \(u^{\prime}v + u\,v^{\prime}\), writing the original factors untouched.
  4. Expand and combine like terms only at the end, once the product rule has done its work.
area = u vv duu dvdu dvuvnegligibledudv
Growth of the area: v du + u dv, plus a corner too small to matter.

Product Rule: solved example

Problem

Differentiate \(y = (2x^3 – x)(x^2 + 5)\).

Solution

Let \(u = 2x^3 – x\), so \(u^{\prime} = 6x^2 – 1\). Let \(v = x^2 + 5\), so \(v^{\prime} = 2x\).

Then \(y^{\prime} = (6x^2 – 1)(x^2 + 5) + (2x^3 – x)(2x) = 6x^4 + 29x^2 – 5 + 4x^4 – 2x^2\).

Combine: \(y^{\prime} = 10x^4 + 27x^2 – 5\). As a check, expanding first gives \(2x^5 + 9x^3 – 5x\), which has the same derivative.

Try it

Question 1

Find the slope of \(y = x^2(4x – 1)\) at \(x = 2\).

Show the answer

\(y^{\prime} = 2x(4x – 1) + x^2(4)\). At \(x = 2\): \(4(7) + 4(4) = 28 + 16 = 44\).

Question 2

Differentiate \(f(x) = x \sin x\).

Show the answer

With \(u = x\) and \(v = \sin x\): \(f^{\prime}(x) = 1 \cdot \sin x + x \cos x = \sin x + x \cos x\).

Product Rule vs. Chain Rule

The product rule is meant for two expressions multiplied side by side, like \(x^2 \cdot \sin x\). The chain rule is for one expression placed inside another, like \(\sin(x^2)\). Ask yourself whether you see a times sign between two functions, or a function whose input is another function.

Chain Rule

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