AP Calculus AB The Chain Rule Worksheet Solutions (PDF)

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This chain rule answers for AP Calculus AB covers the chain rule (Common Core AP CALC AB 3.1), with a free PDF to print.

This answer key gives a full worked solution for every problem in the chain rule worksheet. Compare each step, not only the final answer, because AP graders award credit for a correct setup and clear justification. Final answers are in bold. Redo any problem you missed before moving on to the test.

AP Calculus AB · Common Core State Standards: AP CALC AB 3.1

Chain rule answers: exercises 1 to 10

Exercise 1 – Power of a linear function

Outer function: \(u^{5}\). Inner function: \(u=3x+2\).

Chain rule: \(f^{\prime}(x)=5(3x+2)^{4}\cdot 3\).

Final answer: \(f^{\prime}(x)=15 \left(3 x + 2\right)^{4}\).

Exercise 2 – Power of a quadratic

Outer function: \(u^{3}\). Inner function: \(u=x^{2}-4x\).

Chain rule: \(f^{\prime}(x)=3(x^{2}-4x)^{2}\cdot(2x-4)\).

Final answer: \(f^{\prime}(x)=3 \left(2 x – 4\right) \left(x^{2} – 4 x\right)^{2}\).

Exercise 3 – Square root of a linear function

Outer function: \(\sqrt{u}\). Inner function: \(u=5x-1\).

Chain rule: \(f^{\prime}(x)=\frac{1}{2\sqrt{5x-1}}\cdot 5\).

Final answer: \(f^{\prime}(x)=\frac{5}{2 \sqrt{5 x – 1}}\).

Exercise 4 – Reciprocal power

Rewrite: \(f(x)=(2x+3)^{-2}\).

Outer function: \(u^{-2}\). Inner function: \(u=2x+3\).

Chain rule: \(f^{\prime}(x)=-2(2x+3)^{-3}\cdot 2\).

Final answer: \(f^{\prime}(x)=- \frac{4}{\left(2 x + 3\right)^{3}}\).

Exercise 5 – Sine of a multiple

Outer function: \(\sin u\). Inner function: \(u=4x\).

Chain rule: \(f^{\prime}(x)=\cos(4x)\cdot 4\).

Final answer: \(f^{\prime}(x)=4 \cos{\left(4 x \right)}\).

Exercise 6 – Cosine of a power

Outer function: \(\cos u\). Inner function: \(u=x^{2}\).

Chain rule: \(f^{\prime}(x)=-\sin(x^{2})\cdot 2x\).

Final answer: \(f^{\prime}(x)=- 2 x \sin{\left(x^{2} \right)}\).

Exercise 7 – Exponential with a multiple

Outer function: \(e^{u}\). Inner function: \(u=3x\).

Chain rule: \(f^{\prime}(x)=e^{3x}\cdot 3\).

Final answer: \(f^{\prime}(x)=3 e^{3 x}\).

Exercise 8 – Bell curve

Outer function: \(e^{u}\). Inner function: \(u=-x^{2}\).

Chain rule: \(f^{\prime}(x)=e^{-x^{2}}\cdot(-2x)\).

Final answer: \(f^{\prime}(x)=- 2 x e^{- x^{2}}\).

At \(x=0\) the factor \(-2x\) is \(0\), which matches the peak of the bell curve.

Exercise 9 – Log of a linear function

Outer function: \(\ln u\). Inner function: \(u=5x+2\).

Chain rule: \(f^{\prime}(x)=\frac{1}{5x+2}\cdot 5\).

Final answer: \(f^{\prime}(x)=\frac{5}{5 x + 2}\).

Exercise 10 – Log of a quadratic

Outer function: \(\ln u\). Inner function: \(u=x^{2}+1\).

Chain rule: \(f^{\prime}(x)=\frac{1}{x^{2}+1}\cdot 2x\).

Final answer: \(f^{\prime}(x)=\frac{2 x}{x^{2} + 1}\).

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ln(x² + 1) and its derivative.

Exercises 11 and up

Exercise 11 – Sine squared

Outer function: \(u^{2}\). Inner function: \(u=\sin x\).

Chain rule: \(f^{\prime}(x)=2\sin x\cdot\cos x\).

Final answer: \(f^{\prime}(x)=2 \sin{\left(x \right)} \cos{\left(x \right)}\).

This equals \(\sin 2x\) by a double-angle identity.

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sin² x and its derivative sin 2x.

Exercise 12 – Tangent of a multiple

Outer function: \(\tan u\). Inner function: \(u=3x\).

Chain rule: \(f^{\prime}(x)=\sec^{2}(3x)\cdot 3\).

Final answer: \(f^{\prime}(x)=3 \sec^{2}{\left(3 x \right)}\).

Exercise 13 – Sine of an exponential

For \(f\): outer \(\sin u\), inner \(e^{x}\), so \(f^{\prime}(x)=\cos(e^{x})\cdot e^{x}\).

For \(g\): outer \(e^{u}\), inner \(\sin x\), so \(g^{\prime}(x)=e^{\sin x}\cos x\).

Final answer: \(f^{\prime}(x)=e^{x}\cos(e^{x})\) and \(g^{\prime}(x)=e^{\sin x}\cos x\).

Exercise 14 – Three layers

Layers: cube, cosine, then \(2x\). Work from the outside:

\(f^{\prime}(x)=3\cos^{2}(2x)\cdot(-\sin 2x)\cdot 2\).

Final answer: \(-6\cos^{2}(2x)\sin(2x)\).

Exercise 15 – Chain inside a product

Product rule with \(u=x^{2}\) and \(v=\sqrt{x^{2}+1}\). By the chain rule, \(v^{\prime}=\frac{2x}{2\sqrt{x^{2}+1}}=\frac{x}{\sqrt{x^{2}+1}}\).

\(f^{\prime}(x)=2x\sqrt{x^{2}+1}+\frac{x^{3}}{\sqrt{x^{2}+1}}=\frac{2x(x^{2}+1)+x^{3}}{\sqrt{x^{2}+1}}\).

Final answer: \(\frac{3x^{3}+2x}{\sqrt{x^{2}+1}}\).

Exercise 16 – Chain inside a quotient

Quotient rule with \(u=e^{2x}\), \(u^{\prime}=2e^{2x}\) (chain rule), \(v=x+1\), \(v^{\prime}=1\).

\(f^{\prime}(x)=\frac{2e^{2x}(x+1)-e^{2x}}{(x+1)^{2}}=\frac{e^{2x}(2x+1)}{(x+1)^{2}}\).

Final answer: \(\frac{e^{2x}(2x+1)}{(x+1)^{2}}\).

Exercise 17 – Composite from a table

Chain rule: \(h^{\prime}(1)=f^{\prime}(g(1))\cdot g^{\prime}(1)=f^{\prime}(3)\cdot 2=(-4)(2)=-8\).

Final answer: \(-8\).

functionvalue at pointderivativeg at x = 132f at u = 35-4
Multiply the derivatives along the chain: (−4)(2) = −8.

Exercise 18 – Tangent line with the chain rule

\(y(1)=2^{3}=8\). \(y^{\prime}=3(x^{2}+1)^{2}\cdot 2x=6x(x^{2}+1)^{2}\), so \(y^{\prime}(1)=6\cdot 4=24\).

Tangent: \(y-8=24(x-1)\). Final answer: \(y=24x-16\).

Exercise 19 – Horizontal tangents

Product and chain rules: \(f^{\prime}(x)=e^{-x^{2}/2}+x\cdot e^{-x^{2}/2}\cdot(-x)=e^{-x^{2}/2}(1-x^{2})\).

Since the exponential is never zero, set \(1-x^{2}=0\).

Final answer: \(x=1\) and \(x=-1\).

Exercise 20 – Cooling coffee

\(T^{\prime}(t)=110\cdot e^{-0.05t}\cdot(-0.05)=-5.5e^{-0.05t}\).

\(T^{\prime}(10)=-5.5e^{-0.5}\approx -3.34\).

Final answer: \(T^{\prime}(10)\approx -3.34\text{ °F/min}\): after 10 minutes the coffee is cooling at about 3.34 degrees per minute.

Exercise 21 – Pendulum

\(\theta^{\prime}(t)=0.3\cdot(-\sin 2t)\cdot 2=-0.6\sin 2t\).

At \(t=\frac{\pi}{4}\): \(-0.6\sin\frac{\pi}{2}=-0.6\).

Final answer: \(-0.6\text{ rad/s}\).

Exercise 22 – Nested radicals

Outer: \(\sqrt{u}\) with \(u=x+\sqrt{x}\). Inner derivative: \(1+\frac{1}{2\sqrt{x}}\).

\(f^{\prime}(x)=\frac{1}{2\sqrt{x+\sqrt{x}}}\left(1+\frac{1}{2\sqrt{x}}\right)\).

Final answer: \(\frac{1}{2\sqrt{x+\sqrt{x}}}\left(1+\frac{1}{2\sqrt{x}}\right)\).

Key facts behind this chain rule answers

Key facts
  • Chain rule: dy/dx = f′(g(x)) · g′(x), or dy/du times du/dx.
  • Outer derivative first, inner function unchanged, then multiply by the inner derivative.
  • d/dx e^(g(x)) = e^(g(x)) g′(x) and d/dx ln(g(x)) = g′(x)/g(x).
  • Functions with three layers need the chain rule twice.

How to use this chain rule answers

Cover each solution, solve the exercise again, then uncover it and compare every line. If your answer differs, find the first step that changed and redo the exercise from there.

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All AP Calculus AB chapters: AP Calculus AB math.

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AP Calculus AB The Chain Rule Worksheet Solutions

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