Perpendicular Bisector

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Perpendicular Bisector: meaning, method and solved example (Geometry) – Maths PDF


In short: A perpendicular bisector of a segment is a line that crosses the segment at its midpoint at a right angle, so every point on it is equally far from both endpoints.

GeometryGeometryG-CO.C.9

What is Perpendicular Bisector?

A perpendicular bisector does two jobs at once: it bisects a segment, meeting it exactly at the midpoint, and it is perpendicular to the segment, crossing at \(90^{\circ}\).

Its key property is a distance test. A point lies on the line if and only if it is equidistant from the two endpoints. In coordinates, find the midpoint, then use a slope that is the negative reciprocal of the segment’s slope.

How to spot it

  • A figure shows a small square at the crossing point and matching tick marks on the two halves of the segment.
  • The wording asks for a point equally far from two locations, such as two towns, two wells or two vertices.
  • A coordinate problem asks for the equation of the line that cuts a segment in half at a right angle.
  • A triangle problem needs the circumcenter, where three such lines meet.

The method

  1. Find the midpoint of the segment by averaging the endpoint coordinates.
  2. Find the segment’s slope, then flip it and change its sign to get the perpendicular slope.
  3. Write the line through the midpoint with that slope, in point-slope form, and simplify.
  4. Test a point on the line: its distances to the two endpoints must come out equal.
A(2, -1)B(8, 3)M(5, 1)y = -1.5x + 8.5
The red line meets segment AB at its midpoint M and makes a right angle with it.

Perpendicular Bisector: solved example

Problem

Find the equation of the perpendicular bisector of the segment from \(A(2, -1)\) to \(B(8, 3)\).

Solution

Midpoint: \(\left(\frac{2 + 8}{2}, \frac{-1 + 3}{2}\right) = (5, 1)\). Slope of \(AB\): \(\frac{3 – (-1)}{8 – 2} = \frac{4}{6} = \frac{2}{3}\), so the perpendicular slope is \(-\frac{3}{2}\).

Point-slope form: \(y – 1 = -\frac{3}{2}(x – 5)\), which simplifies to \(y = -\frac{3}{2}x + \frac{17}{2}\). Check with \(P(1, 7)\): \(PA^2 = 1 + 64 = 65\) and \(PB^2 = 49 + 16 = 65\), so \(P\) is equally far from both ends.

Try it

Question 1

A segment has slope \(\frac{5}{4}\). What slope does its perpendicular bisector have?

Show the answer

Flip and negate: \(-\frac{4}{5}\).

Question 2

Point \(X\) lies on the perpendicular bisector of \(\overline{JK}\), and \(XJ = 13\) cm. What is \(XK\)?

Show the answer

Points on the line are equidistant from both endpoints, so \(XK = 13\) cm.

Perpendicular Bisector vs. Angle Bisector

The first one belongs to a segment, halves its length and meets it at \(90^{\circ}\). An angle bisector belongs to a corner, halves a degree measure and need not be perpendicular to anything. Different objects, different halves: one splits a distance, the other splits an opening.

Angle Bisector

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