4th Grade Adding and Subtracting Multi-Digit Numbers Quiz: 10 Questions with Explanations

A \(8,753\)B \(8,853\)C \(4,093\)D \(8,863\)

Ones: 8 + 5 = 13, carry 1. Tens: 7 + 8 + 1 = 16, carry 1. Hundreds: 4 + 3 + 1 = 8. Thousands: 6 + 2 = 8. Forgetting a carry gives 8,753.

A \(4,246\)B \(3,754\)C \(3,764\)D \(3,854\)

Regroup 5,000 as 4 thousands, 9 hundreds, 9 tens, and 10 ones, then subtract each place. Subtracting the smaller digit from the larger in each place gives 4,246.

A \(60,810\)B \(60,710\)C \(59,810\)D \(61,810\)

Ones: 7 + 3 = 10. Tens: 6 + 4 + 1 = 11. Hundreds: 8 + 9 + 1 = 18. Thousands: 4 + 5 + 1 = 10. Ten thousands: 3 + 2 + 1 = 6. Missing the carry from the tens gives 60,710.

A \(4{,}445 + 3{,}759 = 8{,}204\)B \(8{,}204 + 3{,}759 = 4{,}445\)C \(4{,}445 – 3{,}759 = 8{,}204\)D \(3{,}759 – 4{,}445 = 8{,}204\)

To check a subtraction, add the difference to the number subtracted. The sum should equal the starting number.

A \(19,450\)B \(4,550\)C \(5,550\)D \(4,450\)

Subtract the known part from the total: 12,000 – 7,450 = 4,550. Adding gives 19,450, which is more than the total.

A \(60,000\)B \(70,000\)C \(71,077\)D \(80,000\)

29,874 rounds to 30,000 and 41,203 rounds to 40,000. The estimate is 70,000. The exact sum, 71,077, is not an estimate.

A \(6,450\)B \(6,360\)C \(512\)D \(6,460\)

Add: 3,486 + 2,974 = 6,460. Subtracting gives 512, which answers how many more were sold in May.

A \(3,763\)B \(2,247\)C \(2,237\)D \(2,337\)

Ones: 15 – 8 = 7. Tens: 9 – 6 = 3. Hundreds: 9 – 7 = 2. Thousands: 3 – 1 = 2. Skipping the regrouping gives 3,763.

A 7 thousands, 9 hundreds, 9 tens, 9 onesB 7 thousands, 10 hundreds, 10 tens, 0 onesC 7 thousands, 9 hundreds, 9 tens, 10 onesD 6 thousands, 10 hundreds, 10 tens, 10 ones

7,000 + 900 + 90 + 10 = 8,000. The other choices total 7,999, 8,100, and 7,110.

A \(11,425\)B \(11,525\)C \(12,425\)D \(8,575\)

20,000 – 4,750 = 15,250. Then 15,250 – 3,825 = 11,425. The total spent is 8,575, which is not what the question asks.