4th Grade Dividing with Remainders Quiz: 10 Questions with Explanations

A 4B 400C 40D 36

24 tens ÷ 6 = 4 tens, which is 40. Check: 40 × 6 = 240.

A 21 R 2B 21 R 1C 20 R 5D 22 R 1

4 × 21 = 84 and 85 – 84 = 1. A remainder must be less than the divisor, so 20 R 5 is not valid.

A \(47 \div 5 = 9 \text{ R } 4\)B \(47 \div 5 = 2 \text{ R } 9\)C \(47 \div 5 = 9 \text{ R } 2\)D \(47 \div 5 = 8 \text{ R } 7\)

There are 9 full groups of 5 and 2 dots left over: 9 × 5 + 2 = 47.

A 903B 93C 913D 930

4 × 900 = 3,600, and 12 ÷ 4 = 3. So the quotient is 903. Skipping the zero in the tens place gives 93.

A \(7 + 34 = 238\)B \(238 \times 7 = 34\)C \(34 \times 238 = 7\)D \(7 \times 34 = 238\)

Multiplication undoes division: divisor × quotient = dividend. So 7 × 34 = 238.

A 36B 49C 29D 39

The partial quotients are 30 and 9, and 30 + 9 = 39.

A 8B 9C 7D 10

50 ÷ 6 = 8 R 2. The 2 extra photos need another page, so Mei needs 9 pages.

A 0B 6C 3D 5

A remainder must be less than the divisor. If 6 were left over, you could make another group of 6.

A 252B 255C 1,265D 25

1,260 ÷ 5 = 252 because 5 × 252 = 1,260. The number 1,265 comes from adding.

A 62 stickers with 4 left overB 62 stickers with 8 left overC 63 stickers with 4 left overD 15 stickers with 5 left over

Total: 4 × 125 = 500. Then 500 ÷ 8 = 62 R 4, because 8 × 62 = 496.