8th Grade Volume of Cylinders, Cones and Spheres Worksheet Solutions (PDF)

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This volume cylinders cones spheres answers for 8th Grade covers volume of cylinders, cones and spheres (Common Core 8.G.C.9), with a free PDF to print.

This answer key gives a full worked solution for each of the 20 problems on the volume of cylinders, cones and spheres worksheet (Common Core 8.G.C.9). Compare each step with your own work, not only the final answer, and note any step where your method differed.

Grade 8 · Common Core State Standards: 8.G.C.9

Volume cylinders cones spheres answers: exercises 1 to 10

Exercise 1 – Cylinder volume

r = 4 fth = 6 ft
V = 96π ft³.

\(V = \pi \cdot 4^{2} \cdot 6 = 96\pi\).

\(96\pi \text{ ft}^{3}\)

Exercise 2 – Cylinder from a diameter

Radius \(= 5\). \(V = 3.14 \cdot 25 \cdot 7 = 549.5\).

549.5 cm³

Exercise 3 – Cone volume

h = 7 mr = 3 m
V = 21π m³.

\(V = \frac{1}{3}\pi \cdot 9 \cdot 7 = 21\pi\).

\(21\pi \text{ m}^{3}\)

Exercise 4 – Cone from a diameter

Radius \(= 4\). \(V = \frac{1}{3}\pi \cdot 16 \cdot 9 = 48\pi\).

\(48 \cdot 3.14 = 150.72\).

\(48\pi \approx 150.72 \text{ in}^{3}\)

Exercise 5 – Sphere volume

r = 9 in
V = 972π in³.

\(V = \frac{4}{3}\pi \cdot 9^{3} = \frac{4}{3}\pi \cdot 729 = 972\pi\).

\(972\pi \text{ in}^{3}\)

Exercise 6 – Sphere from a diameter

Radius \(= 6\). \(V = \frac{4}{3}\pi \cdot 216 = 288\pi\).

\(288 \cdot 3.14 = 904.32\).

\(288\pi \approx 904.32 \text{ in}^{3}\)

Exercise 7 – Find the height

\(150\pi = \pi \cdot 25 \cdot h\), so \(h = 6\).

6 cm

Exercise 8 – Find the cone height

\(100\pi = \frac{1}{3}\pi \cdot 25 \cdot h\), so \(300 = 25h\) and \(h = 12\).

12 inches

Exercise 9 – Find the radius of a sphere

\(\frac{4}{3}\pi r^{3} = \frac{256}{3}\pi\), so \(r^{3} = 64\).

4 units

Exercise 10 – Cylinder and cone

Cylinder: \(\pi \cdot 16 \cdot 9 = 144\pi\). Cone: \(\frac{1}{3} \cdot 144\pi = 48\pi\).

The cone is one third of the cylinder

Exercises 11 and up

Exercise 11 – Hemisphere

Half a sphere: \(\frac{1}{2} \cdot \frac{4}{3}\pi \cdot 216 = 144\pi\).

\(144\pi\)

Exercise 12 – Soup can

Radius \(= 3.5\). \(V = 3.14 \cdot 12.25 \cdot 4 = 153.86\).

about 153.9 in³

Exercise 13 – Water tank

\(V = \pi \cdot 16 \cdot 10 = 160\pi\).

\(160 \cdot 3.14 = 502.4\).

\(160\pi \approx 502.4 \text{ ft}^{3}\)

Exercise 14 – Ice cream

Cone: \(\frac{1}{3}\pi \cdot 4 \cdot 6 = 8\pi\).

Scoop: \(\frac{4}{3}\pi \cdot 8 = \frac{32}{3}\pi\).

Cone \(8\pi\) in³; scoop \(\frac{32}{3}\pi\) in³

Exercise 15 – Soccer ball

\(V = \frac{4}{3} \cdot 3.14 \cdot 4.5^{3} = \frac{4}{3} \cdot 3.14 \cdot 91.125 = 381.51\).

about 381.5 in³

Exercise 16 – Grain silo

Cylinder: \(\pi \cdot 25 \cdot 20 = 500\pi\). Hemisphere: \(\frac{2}{3}\pi \cdot 125 = \frac{250}{3}\pi\).

Total: \(500\pi + \frac{250}{3}\pi = \frac{1750}{3}\pi\).

\(\frac{1750}{3}\pi \approx 1831.7 \text{ ft}^{3}\)

Exercise 17 – Traffic cone

\(V = \frac{1}{3}\pi \cdot 36 \cdot 18 = 216\pi \approx 678.24\).

about 678.24 in³

Exercise 18 – Swimming pool

\(V = \pi \cdot 36 \cdot 4 = 144\pi \approx 452.16\).

about 452.2 ft³

Exercise 19 – Double the radius

Original: \(\pi \cdot 4 \cdot 5 = 20\pi\). New (\(r = 4\)): \(\pi \cdot 16 \cdot 5 = 80\pi\).

The volume is 4 times as large

Exercise 20 – Find the height with 3.14

\(502.4 = 3.14 \cdot 16 \cdot h = 50.24h\), so \(h = 10\).

10 feet

Key facts behind this volume cylinders cones spheres answers

Key facts
  • Cylinder: \(V = \pi r^{2} h\).
  • Cone: \(V = \frac{1}{3}\pi r^{2} h\), one third of the matching cylinder.
  • Sphere: \(V = \frac{4}{3}\pi r^{3}\); hemisphere: \(\frac{2}{3}\pi r^{3}\).
  • Radius is half the diameter; cube or square the radius before multiplying.
  • Doubling the radius multiplies cylinder volume by 4 and sphere volume by 8.

How to use this volume cylinders cones spheres answers

Cover each solution, solve the exercise again, then uncover it and compare every line. If your answer differs, find the first step that changed and redo the exercise from there.

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