Elimination Method

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Elimination Method: meaning, method and solved example (8th Grade) – Maths PDF


In short: Elimination method solves a system by adding or subtracting the equations so that one variable cancels, leaving one equation in a single unknown.

8th GradeAlgebra8.EE.C.8b

What is Elimination Method?

The elimination method exploits a simple fact: adding equal amounts to both sides of an equation keeps it true. Add two equations of a system together and, if one variable has opposite coefficients, that variable vanishes.

In \(2x + 3y = 23\) and \(4x – 3y = 1\), the terms \(+3y\) and \(-3y\) cancel when you add, giving \(6x = 24\). When no variable cancels at first, multiply one or both equations by a number to create matching or opposite coefficients.

How to spot it

  • The elimination method fits when both equations have x and y terms on the left and a number on the right.
  • One variable has equal or opposite coefficients in the two equations.
  • No variable is isolated, so substitution would involve awkward fractions.
  • Multiplying one equation by a small whole number would line up a pair of coefficients.

The method

  1. To run the elimination method, line up the equations so like terms sit in the same columns.
  2. Multiply one or both equations so a variable has opposite coefficients.
  3. Add the equations to eliminate that variable, and solve for the other one.
  4. Substitute the value into either original equation to find the remaining variable, then check both.
2x + 3y = 234x – 3y = 16x + 0y = 24++3y and -3y cancelx = 24 ÷ 6 = 42(4) + 3y = 23y = 5Solution: (4, 5)
Adding the equations removes y, giving 6x = 24, so x = 4 and then y = 5.

Elimination Method: solved example

Problem

Solve the system \(2x + 3y = 23\) and \(4x – 3y = 1\) by elimination.

Solution

The y-terms are \(3y\) and \(-3y\), so add the equations: \(6x = 24\) and \(x = 4\).

Put \(x = 4\) into the first: \(8 + 3y = 23\), so \(y = 5\). Check the second: \(16 – 15 = 1\). The solution is \((4, 5)\).

Try it

Question 1

Solve \(x + 2y = 11\) and \(3x – y = 12\). Hint: multiply the second equation by 2 first.

Show the answer

The second becomes \(6x – 2y = 24\). Add to the first: \(7x = 35\), so \(x = 5\); then \(5 + 2y = 11\) gives \(y = 3\).

Question 2

In the example, why was addition used instead of subtraction?

Show the answer

The y coefficients, 3 and -3, were opposites, so adding made them cancel; subtracting would have doubled the y terms.

Elimination Method vs. Substitution Method

Elimination combines whole equations to cancel a variable, and works best when both equations are lined up in the form Ax + By = C. Substitution plugs an expression into the other equation, and works best when one variable is already alone. Elimination also makes it easy to spot systems with no solution: both variables vanish and a false statement remains.

Substitution Method

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