Precalculus Logarithms and Their Properties Worksheet Solutions (PDF)
This precalculus logarithms answers for Precalculus covers logarithms and their properties (Common Core F-LE.A.4, F-IF.C.7e, F-BF.B.5), with a free PDF to print.
Precalculus · Common Core State Standards: F-LE.A.4, F-IF.C.7e, F-BF.B.5
Precalculus logarithms answers: exercises 1 to 10
Exercise 1 – Exponential to log form
The base is 2, the exponent is 5 and the result is 32.
\(\log_{2}32=5\)
Exercise 2 – Log to exponential form
The base is the base; the log is the exponent.
\(3^{4}=81\) and \(5^{-2}=\frac{1}{25}\)
Exercise 3 – Evaluate a log
Ask: \(4^{?}=64\). \(4^{3}=64\).
3
Exercise 4 – Log of a fraction
\(2^{-3}=\frac18\).
-3
Exercise 5 – Common and natural logs
\(10^{3}=1000\). \(\ln e^{5}=5\) because \(\ln\) undoes \(e^{x}\).
\(3\) and \(5\)
Exercise 6 – A fractional answer
\(9^{1/2}=3\).
\(\frac12\)
Exercise 7 – Domain
Require \(x-3>0\).
Domain \((3,\infty)\); asymptote \(x=3\)
Exercise 8 – Expand
Quotient rule: \(\log_{2}(8x^{3})-\log_{2}y\). Product and power rules: \(\log_{2}8+3\log_{2}x-\log_{2}y\). Since \(\log_{2}8=3\):
\(3+3\log_{2}x-\log_{2}y\)
Exercise 9 – Condense
Power rule: \(\log x^{2}+\log y-\log z^{3}\). Then product and quotient rules.
\(\log\frac{x^{2}y}{z^{3}}\)
Exercise 10 – Use given values
\(\log_{b}6=0.30+0.48=0.78\). \(\log_{b}1.5=\log_{b}\frac32=0.48-0.30=0.18\). \(\log_{b}8=3(0.30)=0.90\).
\(0.78,\ 0.18,\ 0.90\)
Exercises 11 and up
Exercise 11 – Change of base
\(\frac{\ln 20}{\ln 3}=\frac{2.9957}{1.0986}\approx 2.727\).
\(2.727\)
Exercise 12 – Inverse functions
The inverse swaps coordinates: \((8,3)\). Check: \(\log_{2}8=3\).
\((8,3)\)
Exercise 13 – Transformed log graph
The graph is \(\log_{2}x\) shifted left 1 and down 2. Asymptote \(x=-1\). \(y=0\): \(\log_{2}(x+1)=2\), so \(x+1=4\), \(x=3\). \(y\)-intercept: \(\log_{2}1-2=-2\).
\(x=-1\); \((3,0)\); \((0,-2)\)
Exercise 14 – Inverse properties
Exponentials and logs undo each other, and \(\ln 1=0\).
\(7,\ 4,\ 0,\ 3x\)
Exercise 15 – Powers inside logs
\(\log_{2}16^{3}=3\cdot4=12\). \(\log0.01=\log10^{-2}=-2\). \(\left(\frac12\right)^{-3}=8\).
\(12,\ -2,\ -3\)
Exercise 16 – Decibels
The difference is \(50\) dB, so the ratio is \(10^{50/10}=10^{5}\).
\(100{,}000\) times as intense
Exercise 17 – pH
\(-\log(3.2\times10^{-4})\approx 3.49\). For pH 8: \([\text{H}^{+}]=10^{-8}\).
pH \(\approx 3.5\); \(10^{-8}\)
Exercise 18 – Magnitude difference
\(7-5=2\), so \(10^{2}\).
\(100\) times
Exercise 19 – Verify a property
\(12=4\cdot3\), so \(\log_{2}12=\log_{2}4+\log_{2}3=2+\log_{2}3\approx2+1.585\).
\(\approx 3.585\)
Exercise 20 – Solve for the base or argument
(a) \(x^{4}=81\), \(x=3\). (b) \(2^{-4}=\frac{1}{16}\). (c) \(5^{3}=125\).
(a) \(3\); (b) \(\frac1{16}\); (c) \(3\)
Key facts behind this precalculus logarithms answers
- log_b x = y if and only if b^y = x (b > 0, b not 1, x > 0).
- log_b 1 = 0 and log_b b = 1.
- Product rule adds logs, quotient rule subtracts, power rule multiplies.
- Change of base: log_b M = ln M / ln b.
- The graph of log_b x has the vertical asymptote x = 0 and passes through (1, 0).
How to use this precalculus logarithms answers
Cover each solution, solve the exercise again, then uncover it and compare every line. If your answer differs, find the first step that changed and redo the exercise from there.
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