4th Grade Area and Perimeter of Rectangles Worksheet Solutions (PDF)
This area perimeter answers for 4th Grade covers area and perimeter of rectangles (Common Core 4.MD.A.3), with a free PDF to print.
Grade 4 · Common Core State Standards: 4.MD.A.3
Area perimeter answers: exercises 1 to 10
Exercise 1 – Count the squares
There are 3 rows with 5 squares each: \(3 \times 5 = 15\).
15 square units
Exercise 2 – Area of a rectangle
\(A = l \times w = 7 \times 3 = 21\).
21 sq in
Exercise 3 – Perimeter by adding
\(6 + 2 + 6 + 2 = 16\).
16 ft
Exercise 4 – Perimeter formula
\(P = 2 \times 9 + 2 \times 4 = 18 + 8 = 26\).
26 yd
Exercise 5 – Area of a square
A square is a rectangle with equal sides: \(6 \times 6 = 36\).
36 sq in
Exercise 6 – Perimeter of a square
\(4 \times 8 = 32\).
32 ft
Exercise 7 – Find the area
\(12 \times 5 = 60\).
60 sq ft
Exercise 8 – Find the perimeter
\(2 \times 12 + 2 \times 5 = 24 + 10 = 34\).
34 ft
Exercise 9 – Complete the table
- \(10 \times 4 = 40\); \(2 \times 10 + 2 \times 4 = 28\)
- \(9 \times 6 = 54\); \(2 \times 9 + 2 \times 6 = 30\)
- \(11 \times 2 = 22\); \(2 \times 11 + 2 \times 2 = 26\)
40 sq in and 28 in; 54 sq in and 30 in; 22 sq in and 26 in
Exercise 10 – Missing width
Divide the area by the length: \(48 \div 8 = 6\). Check: \(8 \times 6 = 48\).
6 ft
Exercises 11 and up
Exercise 11 – Missing length
\(72 \div 9 = 8\). Check: \(8 \times 9 = 72\).
8 in
Exercise 12 – Missing side from perimeter
Two lengths: \(2 \times 9 = 18\).
Left for two widths: \(30 – 18 = 12\).
One width: \(12 \div 2 = 6\).
6 in
Exercise 13 – Same area, many shapes
Pairs with product 18: 1 by 18, 2 by 9, 3 by 6.
- \(2 \times 1 + 2 \times 18 = 38\)
- \(2 \times 2 + 2 \times 9 = 22\)
- \(2 \times 3 + 2 \times 6 = 18\)
3 by 6 has the smallest perimeter, 18 units
Exercise 14 – Doubling a rectangle
Original: \(5 \times 3 = 15\) sq ft; \(2 \times 5 + 2 \times 3 = 16\) ft.
Doubled: 10 ft by 6 ft. Area \(10 \times 6 = 60\) sq ft; perimeter \(2 \times 10 + 2 \times 6 = 32\) ft.
15 sq ft and 16 ft; 60 sq ft and 32 ft
Exercise 15 – Garden fence
Perimeter: \(2 \times 14 + 2 \times 9 = 28 + 18 = 46\) ft.
Cost: \(46 \times 3 = 138\) dollars.
46 ft of fence; $138
Exercise 16 – Bedroom carpet
Area: \(12 \times 10 = 120\) sq ft.
Cost: \(120 \times 2 = 240\) dollars.
$240
Exercise 17 – Fence for a garden plot
Width: \(96 \div 12 = 8\) ft.
Perimeter: \(2 \times 12 + 2 \times 8 = 24 + 16 = 40\) ft.
40 ft
Exercise 18 – Poster board
Ribbon is around the edge: \(2 \times 28 + 2 \times 22 = 56 + 44 = 100\) in.
Paper covers the front: \(28 \times 22 = 616\) sq in.
100 in of ribbon; 616 sq in of paper
Exercise 19 – Patio tiles
Area: \(15 \times 8 = 120\) tiles.
Boxes: \(120 \div 20 = 6\).
6 boxes
Exercise 20 – Dog pen
Two lengths: \(2 \times 10 = 20\).
Two widths: \(36 – 20 = 16\), so one width is \(16 \div 2 = 8\) ft.
Area: \(10 \times 8 = 80\) sq ft.
Width 8 ft; area 80 sq ft
Key facts behind this area perimeter answers
- Area of a rectangle = length × width, measured in square units.
- Perimeter of a rectangle = 2 × length + 2 × width, measured in plain units.
- A square is a rectangle whose four sides are equal.
- If you know the area and one side, divide to find the other side.
- Area tells how much to cover; perimeter tells how far around.
How to use this area perimeter answers
Cover each solution, solve the exercise again, then uncover it and compare every line. If your answer differs, find the first step that changed and redo the exercise from there.
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All Grade 4 chapters: Grade 4 math.
