5th Grade Multiplying Multi-Digit Whole Numbers Lesson (Free PDF)

5th Grade math lesson: Multiplying Multi-Digit Whole Numbers – Maths PDF


To multiply multi-digit whole numbers, use the standard algorithm. Multiply the top number by each digit of the bottom number, writing a placeholder zero for each place after the ones. These results are partial products. Add the partial products to find the answer, and estimate first so you can check that the answer is reasonable.

Grade 5 · Common Core State Standards: 5.NBT.B.5

Key facts
  • A partial product comes from multiplying by one digit of the bottom number.
  • Write a placeholder zero when you multiply by tens, hundreds and so on.
  • Add all partial products to get the final product.
  • Estimate by rounding each factor to its greatest place before you multiply.
  • An area model splits each factor by place value and shows the same partial products.

What is the standard algorithm for multiplication?

The standard algorithm is a short way to multiply big numbers. Multiply the top number by each digit of the bottom number. Each result is a partial product. Then add the partial products to get the answer.

Key words
  • Factor: a number you multiply.
  • Partial product: the result of multiplying by one digit of the bottom number.
  • Placeholder: a zero that keeps digits in the right place.
  • Product: the final answer to a multiplication.

How do you multiply by a two-digit number?

Multiply \(412\times38\).

  1. Estimate first: \(400\times40=16{,}000\).
  2. Multiply by the 8 ones: \(412\times8=3{,}296\).
  3. Write a 0 in the ones place as a placeholder. Then multiply by the 3 tens: \(412\times30=12{,}360\).
  4. Add the partial products: \(3{,}296+12{,}360=15{,}656\).
  5. Compare with the estimate. 15,656 is close to 16,000, so the answer makes sense.

The product is 15,656.

41238×3296412 × 812360412 × 3015656
Two partial products add to 15,656.

Why do we write a zero in the second row?

The 3 in 38 stands for 3 tens, or 30. So the second row is \(412\times30\), not \(412\times3\). The zero is a placeholder. It keeps every digit in its correct place.

412 × 3 = 1,236× 10412 × 30 = 12,360
The placeholder zero shifts the row one place left.

How does an area model match the algorithm?

Split each factor by place value: \(412=400+10+2\) and \(38=30+8\). Draw a rectangle with six parts. Each small rectangle is one partial product. When you add all six, you get the same total, 15,656. The area model shows why the algorithm works.

4001023012,0003006083,2008016
Add all six: 15,656.

How do you estimate a product?

Round each factor to its greatest place. Then multiply the rounded numbers. Here 412 rounds to 400 and 38 rounds to 40. The estimate is \(400\times40=16{,}000\). If your exact answer is far from the estimate, check your work for a missing placeholder zero or a carrying mistake. For example, if a friend says \(412\times38=1{,}566\), you can see right away that this is far too small, because the estimate is about 16,000.

412 → 40038 → 40400 × 40 = 16,000
The estimate is 16,000.

Questions about multiplying multi-digit whole numbers

What is a partial product?

A partial product is the answer you get when you multiply the top number by one digit of the bottom number. In \(412\times38\), the partial products are \(412\times8=3{,}296\) and \(412\times30=12{,}360\). You add them at the end.

Why do I write a zero in the second row?

The second row multiplies by tens, so the answer must be 10 times larger. The zero holds the ones place so the other digits shift one place left. Without it, you get an answer that is far too small.

How do I estimate a product?

Round each factor to its greatest place value, then multiply the rounded numbers. For \(58\times31\) use \(60\times30=1{,}800\). The exact answer should be close to your estimate.

Does the order of the factors matter?

No. \(23\times45\) and \(45\times23\) both equal 1,035. Many students put the number with fewer digits on the bottom because it gives fewer rows to add.

How can I check my answer?

First compare it with an estimate. Then multiply again with the factors switched, or draw an area model. If both methods give the same product, your answer is very likely right.

All Grade 5 chapters: Grade 5 math.

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