Algebra 1 Literal Equations and Formulas Worksheet Solutions (PDF)

This literal equations answers for Algebra 1 covers literal equations and formulas (Common Core A-CED.A.4, A-REI.A.1), with a free PDF to print.

Algebra 1 · Common Core State Standards: A-CED.A.4, A-REI.A.1
Literal equations answers: exercises 1 to 10
Exercise 1 – Distance formula
Divide both sides by \(r\).
\(t = \frac{d}{r}\)
Exercise 2 – Perimeter of a square
Divide both sides by 4.
\(s = \frac{P}{4}\)
Exercise 3 – Area of a rectangle
Divide both sides by \(l\).
\(w = \frac{A}{l}\)
Exercise 4 – Circumference
Divide both sides by \(2\pi\).
\(r = \frac{C}{2\pi}\)
Exercise 5 – Solve for b
Subtract \(mx\) from both sides.
\(b = y – mx\)
Exercise 6 – Solve for x
Subtract \(b\): \(y – b = mx\).
Divide by \(m\).
\(x = \frac{y – b}{m}\)
Exercise 7 – Perimeter of a rectangle
Subtract \(2w\): \(P – 2w = 2l\).
Divide by 2.
\(l = \frac{P – 2w}{2}\)
Exercise 8 – Area of a triangle
Multiply both sides by 2: \(2A = bh\).
Divide by \(b\).
\(h = \frac{2A}{b}\)
Exercise 9 – Temperature formula
Subtract 32: \(F – 32 = \frac{9}{5}C\).
Multiply by \(\frac{5}{9}\).
\(C = \frac{5}{9}(F – 32)\)
Exercise 10 – Volume of a prism
Divide both sides by \(lw\).
\(h = \frac{V}{lw}\)
Exercises 11 and up
Exercise 11 – General linear form
Subtract \(b\): \(ax = c – b\).
Divide by \(a\).
\(x = \frac{c – b}{a}\)
Exercise 12 – Standard form to slope-intercept
Subtract \(3x\): \(2y = 12 – 3x\).
Divide every term by 2.
\(y = 6 – \frac{3}{2}x\)
Exercise 13 – Variable on both sides
Subtract \(cx\) and \(b\): \(ax – cx = d – b\).
Factor: \(x(a – c) = d – b\).
Divide by \(a – c\).
\(x = \frac{d – b}{a – c}\)
Exercise 14 – Surface area of a cylinder
Subtract \(2\pi r^{2}\): \(S – 2\pi r^{2} = 2\pi rh\).
Divide by \(2\pi r\).
\(h = \frac{S – 2\pi r^{2}}{2\pi r}\)
Exercise 15 – Trapezoid
Multiply by 2: \(2A = (b_{1} + b_{2})h\). Divide by \(h\): \(\frac{2A}{h} = b_{1} + b_{2}\).
Subtract \(b_{2}\): \(b_{1} = \frac{2A}{h} – b_{2}\).
Substitute: \(b_{1} = \frac{2(60)}{6} – 8 = 20 – 8 = 12\).
\(b_{1} = \frac{2A}{h} – b_{2}\); \(b_{1} = 12\)
Exercise 16 – Simple interest
Divide by \(Pr\): \(t = \frac{I}{Pr}\).
Substitute: \(t = \frac{180}{1500(0.04)} = \frac{180}{60} = 3\).
\(t = \frac{I}{Pr}\); 3 years
Exercise 17 – Convert a temperature
Substitute: \(C = \frac{5}{9}(77 – 32) = \frac{5}{9}(45)\).
Multiply: \(C = 25\).
25°C
Exercise 18 – Fence length
\(l = \frac{P – 2w}{2}\).
Substitute: \(l = \frac{46 – 2(9)}{2} = \frac{28}{2} = 14\).
\(l = \frac{P – 2w}{2}\); 14 feet
Exercise 19 – Road trip speed
Divide by \(t\): \(r = \frac{d}{t}\).
Substitute: \(r = \frac{330}{5.5} = 60\).
\(r = \frac{d}{t}\); 60 mph
Exercise 20 – Slope formula
Multiply by \(x_{2} – x_{1}\): \(m(x_{2} – x_{1}) = y_{2} – y_{1}\).
Add \(y_{1}\): \(y_{2} = m(x_{2} – x_{1}) + y_{1}\).
Substitute: \(y_{2} = 3(5 – 1) + 2 = 14\).
\(y_{2} = m(x_{2} – x_{1}) + y_{1}\); \(y_{2} = 14\)
Exercise 21 – Soup can
Divide by \(\pi r^{2}\): \(h = \frac{V}{\pi r^{2}}\).
Substitute: \(h = \frac{90\pi}{\pi (3)^{2}} = \frac{90\pi}{9\pi} = 10\).
\(h = \frac{V}{\pi r^{2}}\); 10 inches
Key facts behind this literal equations answers
- A literal equation contains two or more variables, like a formula.
- Solve for a variable by applying inverse operations to both sides.
- Treat the other letters as if they were numbers.
- When the variable appears in two terms, collect those terms and factor.
- The answer is an expression, not necessarily a number.
How to use this literal equations answers
Cover each solution, solve the exercise again, then uncover it and compare every line. If your answer differs, find the first step that changed and redo the exercise from there.
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