Algebra 1 Literal Equations and Formulas Test with Point Values (PDF)

Algebra 1 math test: Literal Equations and Formulas – Maths PDF


This literal equations test for Algebra 1 covers literal equations and formulas (Common Core A-CED.A.4, A-REI.A.1), with a free PDF to print.

This test checks literal equations and formulas for Common Core A-CED.A.4. It has 9 questions worth 20 points in all, and you have 45 minutes. Write clear steps, because points are awarded for method as well as for the final answer. Leave a few minutes to review.

Time and points

About this test
  • Grade: Algebra 1
  • Chapter: Literal Equations and Formulas
  • Standards: A-CED.A.4, A-REI.A.1
  • Time: 45 minutes
  • Total: 20 points

Literal equations test: questions

Question 1 – Solve for a side [2 pts]

  1. Solve \(V = lwh\) for \(w\). (1 point)
  2. Solve \(y = mx + b\) for \(m\). (1 point)

Question 2 – Standard form [2 pts]

Solve \(4x + 5y = 20\) for \(y\).

Question 3 – Trapezoid height [2 pts]

Solve \(A = \frac{1}{2}h(a + b)\) for \(h\).

Question 4 – Variable on both sides [2 pts]

Solve \(ax – 3 = bx + 7\) for \(x\), where \(a \neq b\).

Question 5 – Find the principal [2 pts]

Irt$2250.053 years
Known values.

Simple interest is \(I = Prt\). Solve the formula for \(P\), then find the principal that earns the interest shown in the table.

Question 6 – Interest rate [2 pts]

Simple interest is \(I = Prt\). Mei earns $270 on $1,500 after 3 years. Solve the formula for \(r\) and find the annual rate as a percent.

Question 7 – Trapezoid base [3 pts]

b₂ = 7b₁h = 6
Trapezoid with area 54 square feet.

A trapezoid has area \(A = 54\) square feet, height 6 feet, and bottom base 7 feet. The area formula is \(A = \frac{1}{2}(b_{1} + b_{2})h\).

  1. Solve the formula for \(b_{1}\). (2 points)
  2. Find the top base. (1 point)

Question 8 – Rectangle width [3 pts]

l = 15w
Rectangle with perimeter 50.

A rectangle has perimeter 50 meters and length 15 meters.

  1. Solve \(P = 2l + 2w\) for \(w\). (1 point)
  2. Find the width. (1 point)
  3. Find the area. (1 point)

Question 9 – Find the error [2 pts]

A student solved \(3x + 2y = 12\) for \(y\) and wrote \(y = 12 – 3x\). Explain the error and write the correct equation.

See the solutions: Literal Equations and Formulas test solutions

Key facts behind this literal equations test

Key facts
  • A literal equation contains two or more variables, like a formula.
  • Solve for a variable by applying inverse operations to both sides.
  • Treat the other letters as if they were numbers.
  • When the variable appears in two terms, collect those terms and factor.
  • The answer is an expression, not necessarily a number.

How to use this literal equations test

Time yourself: the test is designed for an average student in 45 minutes. Answer the questions you are sure of first, then come back to the longer ones and check your units.

All Algebra 1 chapters: Algebra 1 math.

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Algebra 1 Literal Equations and Formulas Test with Point Values

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